It is (S/s)3 where S and s are the lengths of the sides of the larger and smaller cubes, respectively.
To find the volume of the smaller cube, we can use the ratio of the volumes of the two cubes. Given that the volume of the larger cube is 250 and the ratio of the volumes is 2:5, we can set up the equation ( \frac{V_{\text{smaller}}}{250} = \frac{2}{5} ). Solving for ( V_{\text{smaller}} ), we get ( V_{\text{smaller}} = 250 \times \frac{2}{5} = 100 ). Therefore, the volume of the smaller cube is 100.
It is 28652616 metres^3.
The ratio of the surface areas of two similar figures is equal to the square of the ratio of their corresponding linear dimensions. Given the surface areas are 27 and 1331, the ratio of their corresponding linear dimensions is the square root of ( \frac{1331}{27} ). Since the volume ratio is the cube of the linear dimension ratio, we can find the larger volume by calculating ( \frac{1331}{27} ) and then multiplying the smaller volume (18) by the cube of that ratio. The larger volume is therefore ( 18 \times \left(\frac{1331}{27}\right)^{\frac{3}{2}} = 486 ).
1mm cube has volume of 1mm3 and a surface area of 6*(1*1) = 6mm²2mm cube has a volume of 8mm3 and a surface area of 6(2*2)=24mm²Ratio for 1mm cube is 6-1 and ratio for 2mm cube is 3-1 ■
When the side length of a cube is increased, the surface area increases at a different rate compared to the volume. The surface area of a cube is given by (6a^2) and the volume by (a^3), where (a) is the length of a side. As the side length increases, the surface area-to-volume ratio decreases, meaning that larger cubes have a lower ratio compared to smaller cubes. This reflects that while more surface area is created, the volume increases even more significantly.
To find the volume of the smaller cube, we can use the ratio of the volumes of the two cubes. Given that the volume of the larger cube is 250 and the ratio of the volumes is 2:5, we can set up the equation ( \frac{V_{\text{smaller}}}{250} = \frac{2}{5} ). Solving for ( V_{\text{smaller}} ), we get ( V_{\text{smaller}} = 250 \times \frac{2}{5} = 100 ). Therefore, the volume of the smaller cube is 100.
It is 28652616 metres^3.
Edge of the larger cube = 32 cm Volume of the larger cube = (32 cm)3 = 32768 cm3 Edge of the smaller cube = 4 cm Volume of the smaller cube = (4 cm)3 = 64 cm3 Since the smaller cubes are cut from the larger cube, volume of all of them will be equal to that of the larger cube. ∴ Total number of smaller cubes × Volume of the smaller cube = Volume of the larger cube ⇒ Total number of smaller cubes = Volume of the larger cube ÷ Volume of the smaller cube ⇒ Total number of smaller cubes = 32768 ÷ 64 = 512 Thus, 512 smaller cubes can be cut from the larger one.
The ratio of the surface areas of two similar figures is equal to the square of the ratio of their corresponding linear dimensions. Given the surface areas are 27 and 1331, the ratio of their corresponding linear dimensions is the square root of ( \frac{1331}{27} ). Since the volume ratio is the cube of the linear dimension ratio, we can find the larger volume by calculating ( \frac{1331}{27} ) and then multiplying the smaller volume (18) by the cube of that ratio. The larger volume is therefore ( 18 \times \left(\frac{1331}{27}\right)^{\frac{3}{2}} = 486 ).
1mm cube has volume of 1mm3 and a surface area of 6*(1*1) = 6mm²2mm cube has a volume of 8mm3 and a surface area of 6(2*2)=24mm²Ratio for 1mm cube is 6-1 and ratio for 2mm cube is 3-1 ■
When the side length of a cube is increased, the surface area increases at a different rate compared to the volume. The surface area of a cube is given by (6a^2) and the volume by (a^3), where (a) is the length of a side. As the side length increases, the surface area-to-volume ratio decreases, meaning that larger cubes have a lower ratio compared to smaller cubes. This reflects that while more surface area is created, the volume increases even more significantly.
No, it is not possible to build a larger cube using exactly nine smaller cubes. A larger cube must have a volume that is a perfect cube itself (e.g., 1^3, 2^3, 3^3, etc.). Nine cubes have a total volume of 9, which does not correspond to the volume of any larger cube, as the next perfect cube is 27 (3^3). Therefore, you cannot form a larger cube with exactly nine smaller cubes.
If two pyramids are similar, the ratio of their volumes is the cube of the ratio of their corresponding edge lengths. Given that the ratio of their edges is 3.11, the ratio of their volumes would be (3.11^3). Calculating this, the volume ratio is approximately 30.3. Thus, the volume of the larger pyramid is about 30.3 times that of the smaller pyramid.
No. The surface to volume ratio of a sphere is always smaller than that of a cube. This is because the sphere has the smallest surface area compared to its volume, while the cube has the largest surface area compared to its volume.
Each cut exposes new surface (that was previously in the interior of the cube) without changing the total volume, so yes. If you have two numbers, and one of them changes when the other doesn't, the ratio between the two numbers will change.
For a cube with edge length, L. Surface area = 6L2. Volume = L3. So ratio of Surface Area / Volume = 6 / L. Therefore, as the side length, L, increases, the ratio will decrease.
3:5