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In the given chemical equation, the reactants are potassium sulfate (K₂SO₄) and lead(II) iodide (PbI₂). These substances undergo a chemical reaction to produce lead(II) phosphate (Pb₃(PO₄)₂) and potassium iodide (KI). The equation seems to be missing proper stoichiometry and may need clarification for accurate balancing.
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
The reactants in the equation are potassium sulfate (K₂SO₄) and lead(II) iodide (PbI₂). These substances react to form lead(II) sulfate (PbSO₄) and potassium iodide (KI) as products.
When lead(II) nitrate (Pb(NO₃)₂) is mixed with potassium iodide (KI) in solution, a double displacement reaction occurs, resulting in the formation of lead(II) iodide (PbI₂), which is a precipitate, and potassium nitrate (KNO₃) in solution. The complete ionic equation for this reaction can be written as: [ \text{Pb}^{2+} (aq) + 2 \text{NO}_3^{-} (aq) + 2 \text{K}^{+} (aq) + 2 \text{I}^{-} (aq) \rightarrow \text{PbI}_2 (s) + 2 \text{K}^{+} (aq) + 2 \text{NO}_3^{-} (aq) ] This equation illustrates the dissociation of the soluble ions in solution and the formation of the insoluble lead(II) iodide precipitate.
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The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
The net ionic equation for the reaction between Pb(NO3)2 and KI is: Pb2+ (aq) + 2I- (aq) -> PbI2 (s) This represents the formation of solid lead(II) iodide.
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
lead nitrate(Pb(NO3)2 + potassium iodide(KI) = lead iodide(PbI) + potassium nitrate (KNO3)
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
The chemical equation is: (K+ + I-)(aq) + (Ag+ + [NO3]-)(aq) --> AgI (s) + (K+ + [NO3]-)(aq) or The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The chemical equation is:2 KI + Pb(NO3)2 = 2 KNO3 + PbI2(s)
The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).