Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
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The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
The net ionic equation for the reaction between Pb(NO3)2 and KI is: Pb2+ (aq) + 2I- (aq) -> PbI2 (s) This represents the formation of solid lead(II) iodide.
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
The chemical reaction between lead nitrate and potassium iodide produces lead iodide and potassium nitrate. The balanced chemical equation is: 2Pb(NO3)2 + 2KI -> 2PbI2 + 2KNO3
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
The balanced equation for the reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) to produce potassium nitrate (KNO3) and lead(II) iodide (PbI2) is: 2KI + Pb(NO3)2 → 2KNO3 + PbI2
The net ionic equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) solutions is: Ag+ + I- -> AgI This equation represents the formation of insoluble silver iodide (AgI) precipitate as a result of the reaction between silver ions and iodide ions.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The balanced chemical equation for this reaction is: 2KI(aq) + Pb(NO3)2(aq) → 2KNO3(aq) + PbI2(s)
The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).