Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". There is no symbol before the 3 in the expression to be evaluated.
Sqrt(x-3) or even sqrt(x)-3 cannot be simplified. And without the value of x, they cannnot be evaluated.
That expression can't be simplified. It has to written, and evaluated, just as it appears in the question: [ sqrt(x + 2) ] + [ sqrt(x + 3) ]
Take the integral of the equation of the curve from each end point to calculate the area under the curve. for example: take the integral from 0 to 5 of the equation x2. the result is 1/3(x3) then that is evaluated at 5 and 0 [plug in x=5 and x=0] subtract the result when you plug in 5 from when you plug in 0 and that should be the area. 1/3(125)-1/3(0)= 41.666
Anything that can be evaluated (calculated) as a number. For example, assuming that "x" and "y" stand for numbers: 3 3 + 1 x + 5 x2 x + 7 square root of (x2 + y2)
24 = 3 x 832 = 8 x 424 x 4 = (3 x 8) x 4= 3 x (8 x 4)= 3 x 32This is possible as the multiplication can be done is either order, the brackets above showing two possible ways of multiplying out 3 x 8 x 4:by doing 3 x 8 first and multiplying the result of that by 4; orby doing 8 x 4 first and multiplying the result of that by 3.In both cases, the result is that of 3 x 8 x 4.
A solution for x in an algebraic expression where the result is 3 might be for example, 4 - x = 1. You can solve by adding "x" to each side of the equation (4 = 1 + x) then subtracting 1 from both sides (3 = x, or x=3).
Sqrt(x-3) or even sqrt(x)-3 cannot be simplified. And without the value of x, they cannnot be evaluated.
Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17
That expression can't be simplified. It has to written, and evaluated, just as it appears in the question: [ sqrt(x + 2) ] + [ sqrt(x + 3) ]
Take the integral of the equation of the curve from each end point to calculate the area under the curve. for example: take the integral from 0 to 5 of the equation x2. the result is 1/3(x3) then that is evaluated at 5 and 0 [plug in x=5 and x=0] subtract the result when you plug in 5 from when you plug in 0 and that should be the area. 1/3(125)-1/3(0)= 41.666
The result would be 12a2b.
Anything that can be evaluated (calculated) as a number. For example, assuming that "x" and "y" stand for numbers: 3 3 + 1 x + 5 x2 x + 7 square root of (x2 + y2)
5 x 3 x 2= 30... dummdumm
24 = 3 x 832 = 8 x 424 x 4 = (3 x 8) x 4= 3 x (8 x 4)= 3 x 32This is possible as the multiplication can be done is either order, the brackets above showing two possible ways of multiplying out 3 x 8 x 4:by doing 3 x 8 first and multiplying the result of that by 4; orby doing 8 x 4 first and multiplying the result of that by 3.In both cases, the result is that of 3 x 8 x 4.
Five - 3 x 3 x 3 x 3 x 3 = 243
-1
2.8