The expression 4 x b x b x b simplifies to 4b^3. This is because when you multiply the coefficients 4 and 1, you get 4. When you multiply the variables b, b, and b, you add the exponents, resulting in b^3. Therefore, 4 x b x b x b equals 4b^3.
A number a multiplied b times (so a x a is b=2, a x a x a is b=3, a x a x a x a is b = 4, and so on) is written as ab. Since 2 is multiplied 4 times, you have 24.
For the denominator, multiply the denominators together. For the numerator, subtract the second numerator multiplied by the first denominator from the first numerator multiplied by the second denominator: a/b - p/q = (a x q - b x p)/b x q eg: 6/7 - 3/4 = (6 x 4 - 7 x 3)/7 x 4 = (24 - 21)/28 = 3/28
okay if x-4=3 then x=7 bcause 4+3=x = 4+3=7 and 7-4=3!
(x - 3)/(12 - 4x) = (x - 3)/[4(3 - x)] = (x - 3)/[-4(x - 3)] = 1/-4 = -(1/4)
It is difficult to answer the question because it is still ambiguous. Putting brackets in helps. So: (3 over 4) x b = 3/4*b = 3*b / 4 YES but 3 over (4 x b) = 3/(4*b) is not 3/4*b
12b
You can use the quadratic formula for an equation of the form a*x^2 + b*x + c = 0. x = (-b +/- sqrt(b^2-4*a*c))/(2*a) In this case: a = 1 b = -3 c = -28 x = (3 +/- sqrt(9 - 4*(-28)))/2 x = (3 +/- sqrt(121))/2 x = (3 +/- 11)/2 x = 7 or -4 Another option is to attempt to simplify the equation into the form (x-a)(x-b) = 0. Sometimes you can do this by observation. For example: 28 = 4*7 7-4 = 3 Thus: (x-7)(x+4)=0 In this case, a and b are known as the "roots" of the equation, with a = 7 and b = -4.
For example, (4.1076 x 10^3)/(2.8 x 10^4) = (4.1076/2.8) x [10 ^(3 - 4)] = 1.467 x 10^-1 or (4.1076 x 10^3)/(2.8 x 10^-4) = (4.1076/2.8) x [10 ^(3 - -4)] = 1.467 x 10^7
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
Use x^a * x^b = x^(a+b). x^3 * x^4 = x^7
A number a multiplied b times (so a x a is b=2, a x a x a is b=3, a x a x a x a is b = 4, and so on) is written as ab. Since 2 is multiplied 4 times, you have 24.
a(b + c) = ab + ac 4 x 53 = 4(50 + 3) = (4 x 50) + (4 x 3) = 200 + 12 = 212
Must split 4-3-3. Banksia: 3 from 6 = 20, 4 from 6 = 15 Wattles: 3 from 5 = 10, 4 from 5 = 5 Waratahs: 3 from 4 = 4, 4 from 4 = 1 Possible combinations: 4 x B, 3 x each W: 15 x 10 x 4 = 600 4 x Wat, 3 each B & War: 5 x 20 x 4 = 400 4 x War, 3 each B & Wat: 1 x 20 x 10 = 200 Your 1200 is correct.
Factors aremultiplicativeterms (i.e., they multiply into all the terms). The easiest way to see this is by example.Example 1:a(b+cd)a is a factor and (b+cd) is a factorExample 2:x2 - 9 = (x-3)(x+3)(x-3) is a factor and (x+3) is a factorHopefully you are beginning to notice you can always wrap parenthesis around a factor without altering the order of operations.Example 3:2a(b)(9n-x)+8This is a trick one, but you can factor out a 2:2a(b)(9n-x)+8 = (1)(2)a(b)(9n-x)+(4)(2) = (2)(ab(9n-x)+4)The factors are: 2 and (ab(9n-x)+4)Example 4:If that +8 wasn't on example 3, what would the factors be?2a(b)(9n-x)They would be:2, a, b, and (9n-x)
Did you mean f(x)=x2-2x+5 ? If so the x value of the vertex is found by using the formula x=-b/2a where a is the coefficient of x^2 and b is the coeffiecient of x x=-(-3)/(2*-2) =3/4 y=-2*(3/4)^2-3*(3/4)+7
Any b from a is calculated as:a!/((a-b)!) x b!The ! sign indicates factorial. In your question a = 11 & b = 5In full the formula gives (11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2)/((6 x 5 x 4 x 3 x 2)(5 x 4 x 3 x 2)This simplifies a bit to (11 x 10 x 9 x 8 x 7)/(5 x 4 x 3 x 2) ie 55440/120 = 462.If they can be in any order then you have to multiply by 120...