You can use the manual method to divide the arc in the odd number of parts.
You probably are thinking of the "rule" method for specifying a function. In roster form, a function might look like this: {(1,3), (2,5), (3,7), (4,9), ...}. To change to the rule form, you need to see the pattern in the function and write it as an algebraic expression. The second numbers in the pairs are the odd numbers starting with 3, but this doesn't really help to write a rule. You need to say that "to find the second number, we double the first number and add 1." This gives the rule {x, (2x+1)} or y= 2x+1. If you are given a rule, you can find the roster simply by picking numbers for x and finding the corresponding values of y. Make up the roster by putting the x-values first and the y-values second in each ordered pair.
For any number n you could use * (n % 2 == 0), which would be true for an even number, false for odd For an integer i, a simpler method would be * (i & 1), which would be true for an odd number, false for even
An odd number minus an odd number is an even number.
it is an odd number
You can use the manual method to divide the arc in the odd number of parts.
You probably are thinking of the "rule" method for specifying a function. In roster form, a function might look like this: {(1,3), (2,5), (3,7), (4,9), ...}. To change to the rule form, you need to see the pattern in the function and write it as an algebraic expression. The second numbers in the pairs are the odd numbers starting with 3, but this doesn't really help to write a rule. You need to say that "to find the second number, we double the first number and add 1." This gives the rule {x, (2x+1)} or y= 2x+1. If you are given a rule, you can find the roster simply by picking numbers for x and finding the corresponding values of y. Make up the roster by putting the x-values first and the y-values second in each ordered pair.
For any number n you could use * (n % 2 == 0), which would be true for an even number, false for odd For an integer i, a simpler method would be * (i & 1), which would be true for an odd number, false for even
27 is an odd number.
An odd number minus an odd number is an even number.
when an odd number is subtracted from an odd number the answer is an even number.
odd
it is an odd number
An odd number times an odd number is an odd number no matter which 2 odds you multiply.
an odd numberSubtracting an odd number from an even number will always result in an odd number.
It is an odd number.
you get an odd number