Each term is the sum of the two terms before it.
That's the famous "Fibonacci" series.
Example 1:+5 - +2Step 1:The opposite of +2 is -2.Step 2:Subtraction becomes addition.Solution:+5 - +2 = +5 + -2 = +3
i0 = 4; in = in-1 - 3
Rule #1 . Use The SAME coefficient in all cases #2 ; When multiplying ; add the radicals #3 ; When dividing subtract the radicals #4 ; When 'nesting' multiply the radicals. Here is an example / 3^(4) X 3^(7) Rule 1 ; '3' is the coefficient Rule 2 ; multiplying 3^(4 + 7) = 3^(11) 4^(5) divide 4 ^(7) Rule 1 ; same doefficient '4; Rule 3 ; 4^(5-7) = 4^(-2) or 1/4^(2) [5^(3)]^(2) Rule 1 ; same coefficient '5' Rule 4 ; Nesting ; 5^(3X2)= 5^(6) NB You CANNOT do 2^*3) X 3^(2) by saying 6^(6) WRONG Answer!!!!!
The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).
n*3; n-1 {Where "n" is the previous answer starting at 1. 1, 1*3=3, 3-1=2, 2*3=6, 6-1=5, 5*3=15, 15-1=14, 14*3=42, 42-1=41.
the rule is plus 2 1/3
Example 1:+5 - +2Step 1:The opposite of +2 is -2.Step 2:Subtraction becomes addition.Solution:+5 - +2 = +5 + -2 = +3
i0 = 4; in = in-1 - 3
The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).
If you mean 2/1 3/2 4/3 5/4 then the next 3 terms are 6/5 7/6 8/7 and the nth term is (n+1)/n
n*3; n-1 {Where "n" is the previous answer starting at 1. 1, 1*3=3, 3-1=2, 2*3=6, 6-1=5, 5*3=15, 15-1=14, 14*3=42, 42-1=41.
3 / 5 * 5 / 3 = 1 This answer was calculated according to the order of operations. Rule 1: First perform any calculations inside parentheses. Rule 2: Next, from left to right, do all multiplications and divisions. Rule 3: Last, from left to right, do all additions and subtractions.
1 2 3 4 5 2 5 8 11 14 ... If this is the sequence, the position-to-term rule is 3n-1. However, it could be another sequence depending on the rest of the terms.
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
+1, +2, +3, +4, +5, +6, +7, +8
The rule is t(n) = 5 + 2*n, where n = 1, 2, 3, ...
The rule of the Fibonacci sequence is simple. Take the previous number in the sequence, and add it to the current number. The sequence starts with 0 and 1. 0, 1 So, add 0+1=1. The sequence now contains three numbers. 0, 1, 1 Now, add 1+1=2. This brings us to four numbers. 0, 1, 1, 2 Add 1 and 2. (1+2=3) 0, 1, 1, 2, 3 Now it gets a bit tricky. Add 2+3=5, so the next number is 5. 0, 1, 1, 2, 3, 5 Continue to add the numbers accordingly. (3+5=8) 0, 1, 1, 2, 3, 5, 8 Proceed. 0, 1, 1, 2, 3, 5, 8, 13, 25, 38, 63, 101, 164...