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Displacement is the area under the v-t graph.
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
The nature of displacement-time graph is parabolic if the acceleration is constant(uniform). When acceleration is constant, displacement is directly proportional to the square of time which results into a parabolic structure of graph.
-- Pick two points on the graph. -- Find the difference in time between the two points. -- Find the difference in displacement between the same two points. -- (Difference in displacement) divided by (difference in time) is the average Speed . You can't tell anything about velocity from the graph except its magnitude, because the graph displays no information regarding the direction of motion.
If the Object is falling at a constant velocity the shape of the graph would be linear. If the object is falling at a changing velocity (Accelerating) the shape of the graph would be exponential- "J' Shape.
A displacement vs. time graph of a body moving with uniform (constant) velocity will always be a line of which the slope will be the value of velocity. This is true because velocity is the derivative (or slope at any time t) of the displacement graph, and if the slope is always constant, then the displacement will change at a constant rate.
A graph of uniform velocity would be a straight line with a constant slope, indicating that the object is moving at a constant speed in a straight line without changing its velocity.
The graph of displacement vs. time for something moving at a constant positive velocity would be a straight line sloping upwards, indicating a linear increase in displacement over time.
The shape of the displacement-time graph for uniform motion is a straight line with a constant slope. This indicates that the object is moving at a constant speed in a straight line.
The velocity-time graph of a body moving with uniform retardation will be a straight line sloping downwards. The slope of the line represents the magnitude of the retardation, and the line intersects the time axis at the initial velocity of the body.
The velocity-time graph for uniform retardation is a straight line with a negative slope. The velocity decreases uniformly over time until it reaches zero. The area under the graph represents the displacement of the object.
A displacement-time graph for a boy traveling with uniform velocity to school would be a straight line that slopes upwards, indicating a constant rate of motion. The y-axis represents displacement (distance from the starting point) and the x-axis represents time. The slope of the line would represent the velocity of the boy.
If the displacement-time graph of a body is a straight line, it indicates that the body is moving with a constant velocity. The slope of the line represents the velocity of the body - a steeper slope indicates a higher velocity.
The area under a velocity-time graph represents the displacement of an object. If the area is positive, the object is moving in the positive direction; if negative, the object is moving in the negative direction. The steeper the slope of the graph, the greater the velocity.
In a displacement-time graph, the gradient represents velocity. In a velocity-time graph, the gradient represents acceleration.
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
An Upward Sloping Straight Line. <3