0
-- Pick two points on the graph.
-- Find the difference in time between the two points.
-- Find the difference in displacement between the same two points.
-- (Difference in displacement) divided by (difference in time) is the average Speed .
You can't tell anything about velocity from the graph except its magnitude, because
the graph displays no information regarding the direction of motion.
What else can I help you with?
What equals the displacement on a velocity-time graph?
Displacement is the area under the v-t graph.
What is the condition of the position-time graph when the velocity-time graph passes through zero?
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
What does area under velocity time graph represents?
The area under a velocity-time graph represents the displacement of an object over a given time interval. This area can be calculated by finding the integral of the velocity function with respect to time. If the graph is above the time axis, the displacement is positive; if it's below, the displacement is negative. The shape of the area can vary depending on the velocity function, leading to different methods for calculating it, such as using geometric shapes or calculus.
How do you find the average velocity on a graph?
The answer depends on what variables the graph shows.
Is average speed the slope of a velocity vs. time graph?
No, average speed is not the slope of a velocity vs. time graph; rather, it is represented by the total distance traveled divided by the total time taken. The slope of a velocity vs. time graph indicates acceleration, which is the change in velocity over time. Average speed can be derived from the area under a speed vs. time graph, but it does not equate to the slope of a velocity vs. time graph.
How can you obtain the average velocity and instantaneous velocity from a displacement - time graph?
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
What does displacement divided by time give you?
The Average Velocity on a position time graph or a velocity time graph.
How can you obtain the average velocity and instantaneous velocity from a displacement time graph?
You cannot because a dispacement-time graph is concerned only with motion in a radial direction; any motion in a transverse direction is completely ignored. For example, an object circling the origin at a fixed distance, even with a variable speed, is always at the same distance from the origin. So the displacement-time graph will be a straight line whose height is the radial distance. A straight line in the distance-time graph is to be interpreted as no motion! Really?!The average velocity in the radial direction is the final displacement minus the starting [initial] displacement, all divided by the difference in time between the two points. The instantaneous velocity in the radial direction is the slope [gradient] of the graph at the point in question.
How can you obtain the average velocity and instantaneous velocity from a displacement -time graph?
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
What is the gradient of a graph in a displacement time and velocity time graphs?
In a displacement-time graph, the gradient represents velocity. In a velocity-time graph, the gradient represents acceleration.
Is displacement the slope of the velocity vs time graph?
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
What equals the displacement on a velocity-time graph?
Displacement is the area under the v-t graph.
Does a steep slope on a displacement vs time graph indicates a very large velocity?
Yes, a steep slope on a displacement vs time graph indicates a large velocity. The slope of a displacement vs time graph represents the velocity of an object because velocity is the rate of change of displacement with respect to time. A steep slope implies that the displacement is changing rapidly over time, resulting in a large velocity.
How can you determine the displacement of an object from a velocity time graph?
The displacement of an object from a velocity-time graph can be determined by finding the area under the velocity-time graph. For example, the displacement over a certain time interval can be calculated by finding the area of the corresponding region under the velocity-time graph. This can be done by calculating the area of the trapezoid or rectangle formed by the graph.
Is Average velocity the slope of the line tangent to the curve on a velocity time graph at a specific instant of time?
No, average velocity is the total displacement divided by the total time taken. The slope of the tangent to the curve on a velocity-time graph at a specific instant of time gives the instantaneous velocity at that moment, not the average velocity.
Velocity is the slope of the displacement vs time graph?
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
How do you get displacement from a displacement graph?
To calculate displacement from a displacement graph, find the area under the curve. If the graph is a straight line, you can subtract the initial position from the final position. If the graph is not a straight line, calculate the integral of the graph to determine the total displacement.
