I presume you mean 1 second after jumping from the plane. Since skydiver's fall, their velocity is generally in a downward direction, so the upward velocity is negative. The formula v = gt, where g is the acceleration due to gravity which is about 32.2 feet per second per second, tells us that after 1 second it would be about -32.2 feet per second.
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When an object falls vertically downward, its velocity increases according to the following equation:2aS=vf2 - vi2 or ,2*10*S=v2, orv=(20S)1/2.There is a second case in which a body is thrown vertically upward, here its velocity decreases as it moves upward. Here its velocity becomes zero as it reaches the highest point
The acceleration of gravity is 9.8 meters per second2 .She moves upward until her upward velocity shrinks to Zero = 1/9.8 second.She then begins to move downward, and waits another 1/9.8 second beforeher foot again touches the floor.She is a projectile in a ballistic trajectory for 2/9.8 = 0.204 second. (rounded)
this cannot be answered metres per second is a velocity, units ms-1, litres per second is a volumetric flowrate, units dm3s-1 you would need the area through which the 'velocity' is flowing to answer that otherwise, litres is dm3 = m3 x 10-3
v2 = u2 + 2as where v = current velocity, u = initial velocity, a = acceleration, and s = displacement. Taking a = - 9.8 ms-2 v2 = 182 - (9.8 x 11 x 2) = 108.4 v = 10.4 ms-1
Well its easiest to think of this in context.If Al was to travel at 1 meter per second for one second, he would have traveled 1 meter.How did we come about this? We multiplied the velocity (1 m/s) by the time (1 sec.) to get 1 meter. The unit of seconds cancel out of the velocity leaving us just with the distance.So to answer your question with a direct formula would be as follows:d = v * t