x + 5y = 3
x - x + 5y = -x + 3
5y = -x + 3
(5y)/5 = (-x + 3)/5
y = -(1/5)x + 3/5 The slope-intercept form, y = mx + b, where (slope) m = - 1/5 and (y-intercept) b is 3/5.
It is a straight line.
That is slope-intercept form of a line.
The equation of the line is written in the standard form, y = mx+c
It is a straight line equation in the form of: y = x+5
Slope-line form is: y = -4(x/5 + 1)
It is a straight line.
That is slope-intercept form of a line.
It is a straight line equation in the form of: y = x+5
Slope-line form is: y = -4(x/5 + 1)
It is the equation of a straight line
The equation of the line is written in the standard form, y = mx+c
Yes, that is the slope intercept form of the equation for a straight line.
No, not if the y is squared. When graphed the equation will not form a straight line.
It is a straight line equation and can be rearranged in the form of:- y = -3x+5
y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form