The slope is 2 and the y intercept is -3
-2/3
minus 2 I am starting to see this a lot. The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept. y=-2x+0 the slope (m)= -2, y-intercept (b)= 0
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
y= 1/2x - 2/3
The slope is 2 and the y intercept is -3
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
-2/3
The derivative of x3-2x+5 is 3x2- 2. This is its slope at a point x,y.
minus 2 I am starting to see this a lot. The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept. y=-2x+0 the slope (m)= -2, y-intercept (b)= 0
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
y= 1/2x - 2/3
Minus one half, (-1/2).
If: 4x-2y = 3 then y = 2x-1.5 whereas 2 is the slope and 1.5 is the y intercept
y - 2x is not an equation. If that is supposed to be y = 2x then the slope is 2. Or, written as a slope, would be 2/1
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
2x + y = 20 y = -2x + 20 Slope = -2 m=-2