4x+2y-8=0
2y=8-4x
y=4-2x
slope= -2
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2y = 6x - 8y = 3x - 4========m(slope) = 3=========
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
X = -2(13 + y) / 3x = 5y / 4 - 1
-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4
(3, 2)