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5x + 4y - 8 = 0
Alright, we want to get this in y = mx + b form
subtract 4y from each side
-4y = 5x - 8
divide each side by -4
y = -0.8x + 2
in y = mx + b form, b is the y-intercept and m is the slope.
m directly affects x, while b moves it up and down the y-axis about the origin
therefore, in this problem the slope is -0.8
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What is the slope and y intercept of the equation 5x plus 4y equals 20?
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
How do you change the equation 5x plus 4y equals -4 to slope-intercept form?
5x+4y = -4 4y = -5x -4 y = -5/4x -1 or as y = -1.25x -1 both of which are in slope-intercept form
10 What is the slope of the equation 5x plus 4y 8?
If you mean: 5x+4y = 8 then y = -1.25x+2 therefore the slope is -1.25 and the y intercept is 2
What is the slope given 5x plus 4y equals -2?
5x + 4y = -2Subtract 5x from each side:4y = -5x - 2Divide each side by 4:y = -1.25 x - 0.5In this form, we can look at it and see that the slope of the graph is -1.25and the y-intercept is -0.5 .
What is the slope of the line for the linear equation 5x minus 4y equals 16?
dy/dx = 5/4
