if the x equals -1.2 and the y is -4, 4 what is the slope
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
N = x4 x8 = x4+4 = (x4)2 = N2
23 *n=568*n=56n=56/8n=7
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
The expression "54x10 to the power" is incomplete, as it does not specify the exponent for the power of 10. However, if you're referring to "54 times 10 to the power of n," where n is an integer, it means multiplying 54 by 10 raised to that exponent. For example, if n equals 2, it would be 54 × 10², which equals 5400. Please provide the exponent for a more precise answer.
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
When the equation 2 raised to the power of log n is simplified, it equals n.
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
3 x10 30 x10
3.1 when you round the answer up
The answer depends on which two of (n, x, y) represent the coordinate variables.
This is definitely false; if x=2 and y=3, x to the y power is 8, but y to the x power is 9, which are not equal.
N = x4 x8 = x4+4 = (x4)2 = N2
23 *n=568*n=56n=56/8n=7
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
I presume that since you labeled this as a Calculus problem that you mean x * 4y = 12? x * 4y = 12 ---> 4y = 12 / x ---> y = 3 / x ---> y = 3 * x^(-1) You will notice that this function is not a line, but a curve. The slope will be different at different points on the line. Thus, we can't find the slope of the entire function, but we CAN find a function which gives us the slope of a tangent line at any point on the function. We do this by taking the derivative. For f(x) = a * x^(n) f'(x) = a * n * x^(n-1) Using a = 3 and n = -1, we have: y = f(x) = 3 * x^(-1) dy/dx = f'(x) = 3 * -1 * x^(-1 - 1) = -3 * x^(-2) So your answer will be: dy/dx = -3 * x^(-2)
n=1 is the the lowest level there is.