if the x equals -1.2 and the y is -4, 4 what is the slope
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
N = x4 x8 = x4+4 = (x4)2 = N2
23 *n=568*n=56n=56/8n=7
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
I presume that since you labeled this as a Calculus problem that you mean x * 4y = 12? x * 4y = 12 ---> 4y = 12 / x ---> y = 3 / x ---> y = 3 * x^(-1) You will notice that this function is not a line, but a curve. The slope will be different at different points on the line. Thus, we can't find the slope of the entire function, but we CAN find a function which gives us the slope of a tangent line at any point on the function. We do this by taking the derivative. For f(x) = a * x^(n) f'(x) = a * n * x^(n-1) Using a = 3 and n = -1, we have: y = f(x) = 3 * x^(-1) dy/dx = f'(x) = 3 * -1 * x^(-1 - 1) = -3 * x^(-2) So your answer will be: dy/dx = -3 * x^(-2)
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
When the equation 2 raised to the power of log n is simplified, it equals n.
rearrange the following: A^(1/n)= the nth root of A. eg A to the power 1/2 equals the square root of A. A to the power 1/3 equals the cube root of A. etc.
3 x10 30 x10
3.1 when you round the answer up
The answer depends on which two of (n, x, y) represent the coordinate variables.
This is definitely false; if x=2 and y=3, x to the y power is 8, but y to the x power is 9, which are not equal.
N = x4 x8 = x4+4 = (x4)2 = N2
23 *n=568*n=56n=56/8n=7
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
I presume that since you labeled this as a Calculus problem that you mean x * 4y = 12? x * 4y = 12 ---> 4y = 12 / x ---> y = 3 / x ---> y = 3 * x^(-1) You will notice that this function is not a line, but a curve. The slope will be different at different points on the line. Thus, we can't find the slope of the entire function, but we CAN find a function which gives us the slope of a tangent line at any point on the function. We do this by taking the derivative. For f(x) = a * x^(n) f'(x) = a * n * x^(n-1) Using a = 3 and n = -1, we have: y = f(x) = 3 * x^(-1) dy/dx = f'(x) = 3 * -1 * x^(-1 - 1) = -3 * x^(-2) So your answer will be: dy/dx = -3 * x^(-2)
n=1 is the the lowest level there is.