Q: What is the slope of a line that contains points (44) and (1-2)?

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What is m, the slope of the line that contains the points (6,0), (0,1), and (12,-1)

1 over -10.

Points: (2, 12) Slope: -3 y-12 = -3(x-2) y-12 = -3x+6 y = -3x+6+12 y = -3x+18 which is now in slope intercept form

If the line passing through these points is a straight line then it has a positive gradient.

-12

Related questions

What is m, the slope of the line that contains the points (6,0), (0,1), and (12,-1)

Points: (4, 6) and (12, 3) Slope: -3/8

1 over -10.

Points: (-2, 4) and (-6, 12) Slope: -2

Points: (-12, -17) and (21, 5) Slope: 2/3

Points: (2, 12) Slope: -3 y-12 = -3(x-2) y-12 = -3x+6 y = -3x+6+12 y = -3x+18 which is now in slope intercept form

If the line passing through these points is a straight line then it has a positive gradient.

-12

As a straight line equation: y = -3x+18 in slope intercept form

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Infinite. The line is perpendicular to the ordinate.

If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90