What is m, the slope of the line that contains the points (6,0), (0,1), and (12,-1)
1 over -10.
Points: (2, 12) Slope: -3 y-12 = -3(x-2) y-12 = -3x+6 y = -3x+6+12 y = -3x+18 which is now in slope intercept form
If the line passing through these points is a straight line then it has a positive gradient.
-12
What is m, the slope of the line that contains the points (6,0), (0,1), and (12,-1)
Points: (4, 6) and (12, 3) Slope: -3/8
1 over -10.
Points: (-2, 4) and (-6, 12) Slope: -2
Points: (-12, -17) and (21, 5) Slope: 2/3
Points: (2, 12) Slope: -3 y-12 = -3(x-2) y-12 = -3x+6 y = -3x+6+12 y = -3x+18 which is now in slope intercept form
If the line passing through these points is a straight line then it has a positive gradient.
-12
As a straight line equation: y = -3x+18 in slope intercept form
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Infinite. The line is perpendicular to the ordinate.
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90