If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Slope: -5 Points: (6, 3) Equation: y = -5x+33
Point: (2, -1) Slope: -5 Equation: y = -5x+9
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
y=2x+13
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
Slope: -5 Points: (6, 3) Equation: y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
Slope: -3 Point: (4, -5) Equation: y = -3x+7
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y=2x+1
Equation: y-3 = -5(x-6) => y = -5x+33
Equation: y-3 = -5(x-6) => y = -5x+33