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This is called the gradient.

y=mx + c is the equation for a straight line. x= gradient and c= your y intercept(where the line crosses the y (vertical) axis).

To work out the gradient from to ponts upon a straight line use this simple equation:

y(2) - y(1)/ X(2) - X(1)

Below is a worked example:

Let (X1, Y1) = (-4,5) and (X2,Y2) = (4,17)

So;

(17-5)/(4-(-4))

=

12/8

=

1.5

So your equation y=mx+c = y=1.5x+c

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Q: What is the slope of a line through the pair points?
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