For any two perpendicular lines (save a vertical and a horizontal one), the product of their slopes is always -1. For two perpendicular lines with one having a slope of -2, the other will have a slope equal to -1 divided by -2, which equals 1/2.
-1
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
For any two perpendicular lines (save a vertical and a horizontal one), the product of their slopes is always -1. For two perpendicular lines with one having a slope of -2, the other will have a slope equal to -1 divided by -2, which equals 1/2.
The slope of a perpendicular line is not defined.
-1
No, parallel lines have exactly same slope Perpendicular line have a slope that is negative reciprocal of each other that is if m = slope of line then slope of perpendicular line is -1/m
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
6
They are negative reciprocals. So if the slope of a line is x, the slope of the perpendicular line is -1/x
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
The slope of the perpendicular is -(1/2) .
Slope of a line perpendicular to x-y=16
Any line whose slope is the negative reciprocal of that line's slope will be perpendicular to it. Given the format in which it's written, we can see that this line's slope is -8. This means that any line with a slope of 1/8 will be perpendicular to it. The most obvious one being: y = x/8 + 6 But there are an infinite number of lines with that slope, and thus an infinite number of lines that are perpendicular to the given one. For example, the line: y = x/8 + 258734095874390587423 is just as valid an answer.