2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
2x + 5y = 3 put into standard form wher y = mx + b and m = slope 5y + 2x = 3 5y = -2x + 3 y = -2/5x + 3/5 m = slope = -2/5
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
2X - 5Y = 10 ???? If so. 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
0 = -2x + 5y - 15 -5y = -2x - 15 y = 2x/5 + 3
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
2X - 5Y = 10 subtract 2X from each side - 5Y = - 2X + 10 divide each side by - 5 Y = 2/5X - 2 slope(m) = 2/5
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
2x + 5y = 3 put into standard form wher y = mx + b and m = slope 5y + 2x = 3 5y = -2x + 3 y = -2/5x + 3/5 m = slope = -2/5
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================
Equation: y-6 = 2/5(x-10)Solution: 5y = 2x+10
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0