Q: What is the slope of the graph of 4x 8y11?

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The graph of [ y = 4x + 2 ] is a straight line with a slope of 4.Any line with a slope of 4 is parallel to that one, and any line parallel to that one has a slope of 4.

-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .

Slope = 4.In standard slope-intercept form y = mx + b, with m = slope and b = y-intercept.

If you mean: y = 4x+10 then the y intercept is 10 and the slope of the line is 4

-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7

Related questions

Any graph with the slope of -1/2

The graph of [ y = 4x + 2 ] is a straight line with a slope of 4.Any line with a slope of 4 is parallel to that one, and any line parallel to that one has a slope of 4.

-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .

5

Slope = 4.In standard slope-intercept form y = mx + b, with m = slope and b = y-intercept.

If you mean: y = 4x+10 then the y intercept is 10 and the slope of the line is 4

4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4

-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7

-4x + 5y = 10Add 4x to each side:5y = 4x + 10Divide each side by 5:y = 0.8x + 2The graph of this equation is a straight line with [ slope = 0.8 ] and [ y-intercept = 2 ].

1

4x+2y = 12 2y = -4x+12 y = -2x+6 So the y intercept is 6 and the slope is -2

First, solve the equation for y. 4x * 8y = 10 2x * 4y = 5 4y = 5/(2x) y = 5/(16x) Now it is apparent that the slope of the graph is 5/16, so anything else with such a slope works. y = 5/(16x) + 1 works, for example.