That line is horizontal on the graph. Its slope is zero.
That line is horizontal on the graph. Its slope is zero.
y=-5x+8 the slope is -5.
The y intercept is 3, and since your slope is 0, you have a horizontal line.
The slope of the graph of [ y = x + any number ] is 1 .
The slope is zero.
That line is horizontal on the graph. Its slope is zero.
That line is horizontal on the graph. Its slope is zero.
y=-5x+8 the slope is -5.
1
The y intercept is 3, and since your slope is 0, you have a horizontal line.
The slope of the graph of [ y = x + any number ] is 1 .
The equation has no slope. The graph of the equation is a straight line with a slope of -1 .
find the constant of variation and the slope of the given line from the graph of y=2.5x
The graph of the equation is a straight line. 'm' is its slope. 'b' is its y-intercept
The graph of [ y = -3x ] is a straight line, through the origin, with slope of -3 .
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .