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Can the slope of a line be a fraction?
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
What is the slope of the line given by the equation y5x-22?
27
What is the equation of the line containing the points (3 1) (9 3) (27 9)?
The straight line equation works out as: 3y = x
What is the slope of 5x plus 3y equals 27?
The slope is -5/3.
What is the slope for (01) and (27)?
If you mean: (0, 1) and (2, 7) then the slope works out as 3
What is the point-slope equation of a line with slope -4 that contains the point (-27)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
Can the slope of a line be a fraction?
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
Using the point slope formula what is the answer if the line pass through 0-9and-9-6?
Point-slope formula is y-y1=m(x-x1) The problem looks like: y-(-9)=-1/3(x-0) In Standard Form(answer): x+3y=-27
What is the slope of the line given by the equation y5x-22?
27
How can you graph 3x-9y equals 27?
3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
How do you find the equation of a line when given a containing point and slope?
If you know the slope (m) and a point which we'll call x1, y1 then the equation of the line can be found by using the formula y - y1 = m(x - x1)Input the know values and then bring all the unknowns (x and y) to the left hand side and the knowns (the numbers) to the right hand side.For example:* Find the equation of the line that passes through the point (-2 , 5) and has a slope of -4. * Substitute y1 , x1 and m in the point slope form of a line * y - y1 = m(x - x1) * y - 5 = - 4(x - (-2))
What is the equation of the line containing the points (3 1) (9 3) and (27 9)?
The straight line equation works out as: 3y = x
What is the equation of the line containing the points (3 1) (9 3) (27 9)?
The straight line equation works out as: 3y = x
What is the slope of the line between the points (-327) and (-279)?
If you mean points of: (-3, 27) and (-2, 79) then it works out as 52 Any other arrangements of the points will give a different slope.
What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
What is the equation for a line that goes through points -4 16 and 2 -11?
(-4, 16), (2, -11)First, find the slope of the line.m = (y2 - y1)/(x2 - x1) = [16 - (-11)]/(-4 - 2) = 27/-6 = -27/6Use the point-slope form of the equation of the line with m = -27/6, x1 = 2 and y1 = -11.((y - y1) =m(x - x1) substitute;y - (-11) = -(27/6)(x - 2)y + 11 = -(27/6)x + 54/6y + 11 - 11 = -(27/6)x + 9 - 11y = -(27/6)x - 3 This is the slope-intercept form of the equation of the line.The general form of the equation of the line is: Ax + By + C = 0 where A, B, and C are real numbers, and A and B are not both zero.So, you have:y = -(27/6)x - 3y + (27/6)x + 3 = -(27/6)x + (27/6)x - 3 + 3y + (27/6)x + 3 = 0(27/6)x + y + 3 = 0
