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Points: (2, 7) and (4, 4)

Slope: -3/2

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9y ago

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What is the point-slope equation of a line with slope -4 that contains the point (-27)?

If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28


What is slope of the line that passes through 27 and -4-3?

To find the slope of the line that passes through the points (27, y1) and (-4, -3), we first need to clarify the coordinates. Assuming you meant the point (27, y1) where y1 is not provided, we cannot calculate the slope without knowing the y-coordinate of the first point. The slope formula is given by ( m = \frac{y_2 - y_1}{x_2 - x_1} ). If you provide the missing y-coordinate, I can help you find the slope.


Can the slope of a line be a fraction?

Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .


What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?

you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x


Using the point slope formula what is the answer if the line pass through 0-9and-9-6?

Point-slope formula is y-y1=m(x-x1) The problem looks like: y-(-9)=-1/3(x-0) In Standard Form(answer): x+3y=-27


What is the slope of the line given by the equation y5x-22?

27


What is the slope of the line that contains the points (-27) and (23)?

To find the slope of the line that contains the points (-27) and (23), we need the coordinates of these points. Assuming they are (x1, y1) = (-27, y1) and (x2, y2) = (23, y2), the slope (m) is calculated using the formula ( m = \frac{y2 - y1}{x2 - x1} ). Without the y-coordinates, we cannot determine the slope. Please provide the full coordinates for a specific answer.


How can you graph 3x-9y equals 27?

3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.


How do you find the equation of a line when given a containing point and slope?

If you know the slope (m) and a point which we'll call x1, y1 then the equation of the line can be found by using the formula y - y1 = m(x - x1)Input the know values and then bring all the unknowns (x and y) to the left hand side and the knowns (the numbers) to the right hand side.For example:* Find the equation of the line that passes through the point (-2 , 5) and has a slope of -4. * Substitute y1 , x1 and m in the point slope form of a line * y - y1 = m(x - x1) * y - 5 = - 4(x - (-2))


What is the equation of the line containing the points (3 1) (9 3) and (27 9)?

The straight line equation works out as: 3y = x


What is the equation of the line containing the points (3 1) (9 3) (27 9)?

The straight line equation works out as: 3y = x


What is the slope of the line between the points (-327) and (-279)?

If you mean points of: (-3, 27) and (-2, 79) then it works out as 52 Any other arrangements of the points will give a different slope.