Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
Points: (2, 7) and (4, 4) Slope: -3/2
27
Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines
The slope is -5/3.
Of course. If the line rises 18 units for every 27 horizontal units,then its slope is 2/3 .
Points: (2, 7) and (4, 4) Slope: -3/2
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
27
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
3x - 9y = 27-9y = -3x + 279y = 3x - 27y = x/3 - 3The graph is a straight line, with (slope = 3), and passing through the point (y = - 3) on the y-axis.
If you mean points of: (-3, 27) and (-2, 79) then it works out as 52 Any other arrangements of the points will give a different slope.
Point-slope formula is y-y1=m(x-x1) The problem looks like: y-(-9)=-1/3(x-0) In Standard Form(answer): x+3y=-27
(-4, 16), (2, -11)First, find the slope of the line.m = (y2 - y1)/(x2 - x1) = [16 - (-11)]/(-4 - 2) = 27/-6 = -27/6Use the point-slope form of the equation of the line with m = -27/6, x1 = 2 and y1 = -11.((y - y1) =m(x - x1) substitute;y - (-11) = -(27/6)(x - 2)y + 11 = -(27/6)x + 54/6y + 11 - 11 = -(27/6)x + 9 - 11y = -(27/6)x - 3 This is the slope-intercept form of the equation of the line.The general form of the equation of the line is: Ax + By + C = 0 where A, B, and C are real numbers, and A and B are not both zero.So, you have:y = -(27/6)x - 3y + (27/6)x + 3 = -(27/6)x + (27/6)x - 3 + 3y + (27/6)x + 3 = 0(27/6)x + y + 3 = 0
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
Points: (-2, 7) and (3, 6) the slope is -1/5 Points: (4, 2) and (9, 1) the slope is -1/5 Both slopes are the same and so therefore they are parallel lines
If you mean points (x,y) : (-2, 7) and (2, 3) then the slope works out as -1 as the slope = (y2-y1)/(x2-x1) = (3-7)/(2 +2) = -4/4 = -1