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6x+3y = 18 3y = -6x+18 y = -2x+6 Therefore the slope is -2 and the y intercept is 6
y=-18x+17. Since this is already in Slope-Intercept form, we can determine that the slope is negative 18.
A line with equation y = mx + c has slope m (and intercept c), thus convert the given equation into this form: 2x + 3y = 18 ⇒ 3y = -2x + 18 ⇒ y = -2/3x + 6 ⇒ slope is -2/3.
That's the equation of a straight line with a slope of 2/3 and a y-intercept at y=6 .
First calculate the slope of the line itself:18y = 3x + 4y = (1/6)x + (4/18)This line is in slope-intercept form; the slope in this case is 1/6.For the slope of the perpendicular line, take the negative reciprocal, -1 / (1/6), which is equal to -6.