A single point cannot determine the slope of a straight line. It can, therefore, have any slope at all.
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean (4, -1) and (-1, 4) Slope: (-1-4)/(4--1) = -1
To find the equation of a line with a slope of 2 that passes through the point (1, 4), we can use the point-slope form of the equation: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 4 = 2(x - 1)). Simplifying this, the equation of the line is (y = 2x + 2).
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
It is: y = -10x+14
Answer this question… What is the slope of the line that contains the points (-1, 2) and (4, 3)?
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
It is: y = -10x+14
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
It is: y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
"14" is not a point; you need two coordinates to specify a point.
Points: (14, 5) and (20, 4) Slope: -1/6
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2