The slope is 1/2.
Points: (2, -2) and (8, 1)Slope: 1/2
The slope is (6 - 1)/(1 - 2) = 5/(-1) = -5
Another coordinate is needed to work out the slope.
-5/3
The slope is -2/3.
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
Points: (2, 1) and (-4, -5) Slope: (1--5)/(2--4) = 1
Slope = [(-5) - 4]/[2 - (-1)] = -9/3 = -3
The line between the points (3, 4) and (2, 1) has: slope = change_in_y/change_in_x = (4 - 1)/(3 - 2) = 3/1 = 3
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
1/2
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
Perpendicular line = - 1/gradient= - 1/2/3= - 3/2
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
let (2,-5) be P1 and (-1,-8) be P2 Slope is -5+8/2+1=3/3=1
It is: y = 2 which is straight horizontal line with no slope that connects (-1, 2) to (5,2)