The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
The line between the points (3, 4) and (2, 1) has: slope = change_in_y/change_in_x = (4 - 1)/(3 - 2) = 3/1 = 3
It is: (5-4)/(2-0) = 1/2
The slope = (y2 - y1)/(x2 - x1) = (7 - 3)/(4 - 1) = 4/3
find the slop of the line passing through (1,5) and (0,2)
Points: (1, 5) and (0.2)Slope: 3
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
1/2
4/1
Points: (14, 5) and (20, 4) Slope: -1/6
Points: (1, 2) and (3, 8) Slope: 3
1:5
If you mean points of (2, 4) and (4, 2) then the slope is -1
Points: (3, 4) and (2, 1) Slope: 3
Points: (1, 5) and (0, 2) Slope: 3
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5