If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
The general equation of a line is: y = mx + b where m is the slope and b is the y-intercept. 3x + y = 4 y = -3x + 4 The slope is -3.
4
- 1/3
4
If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
3/4
The general equation of a line is: y = mx + b where m is the slope and b is the y-intercept. 3x + y = 4 y = -3x + 4 The slope is -3.
4
The slope would be 3/4
Lines parallel to the line would have the same slope, which is 3/4. (0.75) 3x-4y = 12 3x-12 = 4y y = 3/4 x - 3 The y-intercept is -3 and the slope is 3/4.
- 1/3
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
4/3 First, get this into slope-intercept form (get y by itself). 3x+4y=12 -> Move 3x to the right by subtracting from both sides. -3x -3x 4y=12-3x -> get y alone by dividing everything by 4. 4y=-3x+12 ÷4 ÷4 ÷4 y=(-3/4)x+3 -> The slope is -3/4. To get the perpendicular line's slope you take the slope (-3/4) and flip it and switch the sign: negative becomes positive, 3/4 becomes 4/3.
4
First calculate the slope of the line itself:18y = 3x + 4y = (1/6)x + (4/18)This line is in slope-intercept form; the slope in this case is 1/6.For the slope of the perpendicular line, take the negative reciprocal, -1 / (1/6), which is equal to -6.