Slope of (5,6) and (9,6)
m = (y2- y1)/(x2-x1)
m = (6-6)/(9-5)
m = 0/4
m = 0
Therefore, the slope of this line is 0.
Points: (6, 7) and (-3, 5) Slope = change_in_y/change_in_x = (7 - 5)/(6 - -3) = 2/9
slope is =( 9-15 )/ (5-3) = -6/2 = -3
Points: (6, -7) and (5, -9) Slope: 2
Points do not have a slope but a straight line joining them does: (9-3)/(2- -6) = 6/8 = 3/4 or 0.75
To find the slope of the line passing through the points (5, -6) and (4, 3), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the coordinates, ( m = \frac{3 - (-6)}{4 - 5} = \frac{3 + 6}{4 - 5} = \frac{9}{-1} = -9 ). Therefore, the slope of the line is -9.
Points: (6, -7) and (5, -9) Slope: 2
The slope is -9.
Points: (6, 7) and (-3, 5) Slope = change_in_y/change_in_x = (7 - 5)/(6 - -3) = 2/9
slope is =( 9-15 )/ (5-3) = -6/2 = -3
Points: (6, -7) and (5, -9) Slope: 2
Points do not have a slope but a straight line joining them does: (9-3)/(2- -6) = 6/8 = 3/4 or 0.75
Points: (3, 15) and (5, 9) Slope: -3
Points: (9, 6) and (3, 8) Slope: -1/3
The slope is -9.
Points: (5, 9) and (-3, -3) Slope: 3/2
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Points: (7, 3) and (5, 9) Slope: -3