Q: The slope of the line passing through points (-6 3) and (-6 39) is .?

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If you mean points of (-2, -1) and (3, 5) then the slope is 6/5

If you mean points of (055, 18) and (566, 81) then the slope works out as 9/73

84

The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5

Find the slope of the line passing through (5, 5) and (-4, 5).

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The slope is -9.

17

If the line passing through these points is a straight line then it has a positive gradient.

Another set of points are needed to find the slope.

thanks you for your help

Since the line is horizontal, the slope is zero.

Points: (14, 5) and (20, 4) Slope: -1/6

To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).

Points: (3, 4) and (2, 1) Slope: 3

If you mean points of (-2, -1) and (3, 5) then the slope is 6/5

1:5

That depends on the points in order to find the slope whereas no points have been given.