0
A line with the equation y = -13 is a horizontal line. The slope is zero.
If you think of the "y = mx + b" form of a straight line, the 'b' must be -13, and the 'm' must be zero since there is no x term. 'm' is the slope, so the slope is 0.
If: -11x+y = 13 Then: y = 11x+13 whereas 11 is the slope and 13 is the y intercept
Slope and y-intercept of y equals 2.5x is: Slope is 2.5 and y-intercept is 0
Slope for the equation y equals 7 is zero.
That equation represents only one line. y - 11 = -13x - 7 y = -13x + 4 The slope is -13.
y=x y=1x The slope is one.
If: -11x+y = 13 Then: y = 11x+13 whereas 11 is the slope and 13 is the y intercept
Slope and y-intercept of y equals 2.5x is: Slope is 2.5 and y-intercept is 0
Slope for the equation y equals 7 is zero.
Parallel, the slope of the second equation is 4
4x-5y = 13 -5y = -4x+13 y = 4/5x-13/5 Slope = 4/5 or 0.8
That equation represents only one line. y - 11 = -13x - 7 y = -13x + 4 The slope is -13.
That equation represents only one line. y - 11 = 13x - 7 y = 13x + 4 The slope is 13.
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
y=13x
The slope equals 3
Slope = 0
y=x y=1x The slope is one.