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What is the slope of a perpendicular line if the slope of a line is -13?
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.
Write the equation in slope-intercept form of the line that has a slope of -7 and y-intercept 6?
-13
What is the equation of that line that passes through the centre of the circle 2x2 plus 2y2 -8x -5y -1 equals 0 and is perpendicular to the line 4x plus 9y plus 5 equals 0?
Centre of circle: (2, 1.25) Slope of line: 9/4 Equation of line: y-1.25 = 9/4(x-2) => 4y-5 = 9x-18 => 4y = 9x-13
What is the equation of the line whose coordinates are at 2 3 and 11 13?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
What is the equation of the line that passes through the point -7-3 and is parallel to -5x plus 8y equals 27?
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11
