The line is flat.
A slope has its equation as y2 - y1/x2 - x1. So 4 - -10/5 - 1 = 14/4 = 7/2.
If you mean point of (1, 4) and slope of -10 then y = -10x+14
To find the equation of a line with a slope of 2 that passes through the point (1, 4), we can use the point-slope form of the equation: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 4 = 2(x - 1)). Simplifying this, the equation of the line is (y = 2x + 2).
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If the equation is x + 7y = 14 then the slope is -1/7 If the equation is x + y7 = 14, then the slope is 7(14 - x)-8
Points: (14, 5) and (20, 4) Slope: -1/6
Points: (1, 14) and (3, 4) Slope: (4-14)/(3-1) = -5
"14" is not a point; you need two coordinates to specify a point.
Slope = change in ordinate/change in abscissa = (2 - 16)/(4 - -3) = -14/7 = -2
The parallel equation will have the same slope but with a different y intercept
A slope has its equation as y2 - y1/x2 - x1. So 4 - -10/5 - 1 = 14/4 = 7/2.
8
It is: y = -10x+14
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
It is: y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
Points: (-3, 17) and (5,9) Slope: -1 Equation: y = -x+14