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It is LCM(3, 4, 5, 6) + 2 = 60 + 2 = 62

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10y ago
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6mo ago

The smallest number that leaves a remainder of 2 when divided by 3, 4, 5 or 6 is 62. This can be found by analyzing the multiples of the greatest common divisor (GCD) of 3, 4, 5, and 6, which is 60. Adding 2 to this number gives us the smallest number with the specified remainder.

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Q: What is the smallest number greater than 1that leaves a remainder of 2when divided by 3 or 4 or 5 or 6?
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