44,100
The four smallest positive integers are 1, 2, 3, and 4. To find the smallest positive perfect square divisible by these numbers, we first determine their least common multiple (LCM). The LCM of 1, 2, 3, and 4 is 12. The smallest perfect square greater than or equal to 12 is 36, which is (6^2). Thus, the smallest positive perfect square that is divisible by 1, 2, 3, and 4 is 36.
To find the smallest positive perfect square that is divisible by 2, 3, 5, and 7, we first determine the least common multiple (LCM) of these numbers. The LCM is (2^1 \times 3^1 \times 5^1 \times 7^1 = 210). For a number to be a perfect square, all prime factors must have even exponents. Thus, we square the LCM, yielding (210^2 = 44100). Therefore, the smallest positive perfect square that is divisible by 2, 3, 5, and 7 is 44100.
To find the smallest positive integer ( n ) such that ( 2n ) is a perfect square, ( 3n ) is a perfect cube, and ( 4n ) is a perfect fourth, we analyze the conditions for each case using prime factorization. Let ( n = 2^a \cdot 3^b \cdot k ), where ( k ) is coprime to 2 and 3. For ( 2n ) to be a perfect square, ( a+1 ) must be even and ( b ) must be even. For ( 3n ) to be a perfect cube, ( a ) must be divisible by 3 and ( b+1 ) must be divisible by 3. For ( 4n ) to be a perfect fourth, ( a+2 ) must be divisible by 4 and ( b ) must be divisible by 4. By solving these conditions simultaneously, the smallest ( n ) that meets all conditions is ( n = 108 ).
25 = 9 + 16 There are many more sets like these. This one has the smallest numbers.
divisible by 2
(3x5x7x11)2 =1334025
The four smallest positive integers are 1, 2, 3, and 4. To find the smallest positive perfect square divisible by these numbers, we first determine their least common multiple (LCM). The LCM of 1, 2, 3, and 4 is 12. The smallest perfect square greater than or equal to 12 is 36, which is (6^2). Thus, the smallest positive perfect square that is divisible by 1, 2, 3, and 4 is 36.
44,100
It is 49.
Perfect squares are positive. A smallest negative number doesn't exist. The four smallest prime numbers are 2, 3, 5 and 7. The smallest perfect square would have to be 2^2 x 3^2 x 5^2 x 7^2 or 44,100
To find the smallest positive perfect square that is divisible by 2, 3, 5, and 7, we first determine the least common multiple (LCM) of these numbers. The LCM is (2^1 \times 3^1 \times 5^1 \times 7^1 = 210). For a number to be a perfect square, all prime factors must have even exponents. Thus, we square the LCM, yielding (210^2 = 44100). Therefore, the smallest positive perfect square that is divisible by 2, 3, 5, and 7 is 44100.
3600 is the smallest perfect square divisible by 8,9 and 10. Work out the prime factorisations for each of the numbers 8, 9, 10: 8 = 23 9 = 32 10 = 2 x 5 So the perfect square must be a multiple of the lcm of 8, 9 & 10 = 23 x 32 x 5 to be divisible by all three numbers. All perfect squares have even powers for all their primes (in their prime factorisation), so to make all the powers even the smallest multiplier of this is 2 x 5, giving 24 x 32 x 52 = 3600.
360
To find the smallest positive integer ( n ) such that ( 2n ) is a perfect square, ( 3n ) is a perfect cube, and ( 4n ) is a perfect fourth, we analyze the conditions for each case using prime factorization. Let ( n = 2^a \cdot 3^b \cdot k ), where ( k ) is coprime to 2 and 3. For ( 2n ) to be a perfect square, ( a+1 ) must be even and ( b ) must be even. For ( 3n ) to be a perfect cube, ( a ) must be divisible by 3 and ( b+1 ) must be divisible by 3. For ( 4n ) to be a perfect fourth, ( a+2 ) must be divisible by 4 and ( b ) must be divisible by 4. By solving these conditions simultaneously, the smallest ( n ) that meets all conditions is ( n = 108 ).
the answer is 144, it is divisible by 1, 4, 9, 16, 36, and 144.
25 = 9 + 16 There are many more sets like these. This one has the smallest numbers.
divisible by 2