122.
lcm(3, 4, 5, 6) = 60
Thus need the smallest number greater than or equal to 100 (the first 3-digit number) that is a multiple of 60 plus 2:
100 ÷ 60 = 1 r 40 → smallest multiple of 60 is 60 x 2 = 120
→ required number is 120 + 2 = 122
6172839
85
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
23
Try 30
6172839
85
234568
41
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
23
0.25
Try 30
36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
64 and 76