1 is the answer
The smallest positive integer that has exactly 6 factors is 12. To determine the number of factors an integer has, we can use its prime factorization. In the case of 12, its prime factorization is 2^2 * 3, which means it has (2+1)(1+1) = 6 factors.
The positive integers are {1, 2, 3, 4, 5, ...}. The smallest one is 1.
The smallest positive integer is 1 (a positive integer is a whole number: 1, 2, 3, and so on). But zero may also be considered - depending on circumstances: 0, 1, 2, 3, and so on). Though 1 is my answer.
The smallest positive integer with four different digits is 1023. This number uses the smallest digits available (1, 0, 2, and 3) while ensuring that the first digit is not zero, thus maintaining its status as a positive integer.
6172839
The smallest positive integer that has exactly 6 factors is 12. To determine the number of factors an integer has, we can use its prime factorization. In the case of 12, its prime factorization is 2^2 * 3, which means it has (2+1)(1+1) = 6 factors.
The positive integers are {1, 2, 3, 4, 5, ...}. The smallest one is 1.
The smallest positive integer is 1 (a positive integer is a whole number: 1, 2, 3, and so on). But zero may also be considered - depending on circumstances: 0, 1, 2, 3, and so on). Though 1 is my answer.
The smallest positive integer with four different digits is 1023. This number uses the smallest digits available (1, 0, 2, and 3) while ensuring that the first digit is not zero, thus maintaining its status as a positive integer.
The smallest factor of any positive integer is 1.
6172839
2 is the smallest prime factor of 12.
The greatest positive even integer less than 12 is 10
The smallest divisor of any even integer is 2, since even integers are defined as those that are divisible by 2. This means that every even integer can be expressed in the form of (2k), where (k) is an integer. Consequently, 2 is the smallest positive integer that divides any even number without leaving a remainder.
No. Integers are positive and negative whole numbers (…, -2, -1, 0, 1, 2, …). As there are an infinite number of negative integers as they approach negative infinity (the greatest negative integer being -1), there can be no smallest (negative) integer.
3 = (3)*15 + (-2)*21
Since the smallest integer is 2, the largest one let be x. At least 12 means equal to 12 or larger than 12. So we have this inequality: x - 2 ≥ 12 x - 2 + 2 ≥ 12 + 2 x ≥ 14