The smallest set of such prime numbers is 5, 7, 11, 13, making a sum of 36.
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-210 is a negative, real, rational integer.
No need; it is already rounded.
211.
Let's assume that the three consecutive integers are n-1, n, and n+1. We know that their product is 210, so we can set up the equation (n-1)(n)(n+1) = 210. By solving this equation, we can find that the three integers are 6, 7, and 8. Therefore, the sum of the smallest two integers is 6 + 7 = 13.
Prime numbers, raised to a power, have one more factor than their exponents. The smallest prime number is 2. 210 has eleven factors. 210 = 1024