210/2 = 105
210/3 = 70
210/5 = 42
210/7 = 30
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The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
2 * 3 * 5 * 7 = 210 is the smallest one divisible by four unique prime numbers. However, there are an infinite number of them, since there are an infinite number of primes.
Prime numbers are only divisible by 1 and themselves. Since 3 is not a prime number, any prime number divisible by 3 does not exist. Therefore, the set of prime numbers divisible by 3 is an empty set.
the least number is 210 which is divisible by four different prime numbers.