2 x 2 x 2 = 8
2 x 3 x 5 = 30
210
The smallest factor is 1 because 3 is a prime number making its only factors 3 and 1.
2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216
154
To write 87 as a product of its prime factors, we first divide it by the smallest prime number, which is 3. This gives us 87 = 3 * 29. Since 29 is a prime number itself, the prime factorization of 87 is 3 * 29.
The smallest positive integer is 3.
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
Since 3 is prime, the factors are 1 and 3.
It is: 30
How about: 105
42
210
84
The prime factors of 315 are 3, 3, 5, and 7. To find the prime factors, you can start by dividing 315 by the smallest prime number, which is 2, but since 315 is odd, you move on to the next smallest prime number, which is 3. Dividing 315 by 3 gives you 105, and then further dividing by 3 gives you 35. Finally, dividing 35 by 5 gives you 7, which is a prime number. Therefore, the prime factors of 315 are 3, 3, 5, and 7.
The smallest factor is 1 because 3 is a prime number making its only factors 3 and 1.
2 x 3 x 5 = 30
3 is the smallest odd prime number.