If you mean: 749 = 5q then the value of q is 749/5 = 149.8
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
7+5q = -3 5q = -3-7 5q =-10 q = -2
7p+5q=-3, p=1 7Xp+5q=-3 7+5q=-3 5p=-10 p=-2
If the solutions are p and q, then the quadratic is (x-p)(x-q) = 0 or x2 - (p+q)x + pq = 0 Hope this is what the question meant!
To multiply different expressions, you can just write them side by side, if there is no possibility of confusion (that is, "24" does NOT mean 2 multiplied by 4, so you need a multiplication sign).In this case, you can indicate the multiplication by writing 5q.
5q - 3.75 = 26.25 Therefore, 5q = 30 q = 30/5 q = 6
7+5q = -3 5q = -3-7 5q =-10 q = -2
5q-29 equals 21 5q equals 50 q = 5
3q + 5 + 2q + 5 = 65 5q + 10 = 65 5q = 55 q = 11 Check it. 33 + 5 + 22 + 5 = 65 It checks.
q=-4.
9
7p+5q=-3, p=1 7Xp+5q=-3 7+5q=-3 5p=-10 p=-2
155
If the solutions are p and q, then the quadratic is (x-p)(x-q) = 0 or x2 - (p+q)x + pq = 0 Hope this is what the question meant!
The value of Q in the equation Q = 12 + 89 is 101.
To multiply different expressions, you can just write them side by side, if there is no possibility of confusion (that is, "24" does NOT mean 2 multiplied by 4, so you need a multiplication sign).In this case, you can indicate the multiplication by writing 5q.
There is no simple way which can be easily applied to all forms of equations. If the variable(s) can be eliminated from the equation then, if what is left isfalse, then the equation has no solution.true, then the equation is an identity.The problem is complicated by the domains under consideration. The following are some examples of equations which have no solutions in one domain but do in another [larger] domain:x + 2 = 0 has no solution in N (natural numbers) but does in Z (integers)x*2 = 1 has no solution in Z but does in Q (rational numbers)X^2 = 2 has no solution in Q but does in R (real numbers)x^2 = - 2 has no solution in R but does in C (complex numbers).