-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
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h = -5 -7 * -5 = 35 A negative times a negative equals a positive.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
5.6
It is a basic solution
apexvs answer 3.3
It's a simple linear equation in 'h' .Its solution is [ h = 4 ].
f = 54
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The pH of a solution is calculated using the formula pH = -log[H+]. Plugging in the given value of [H+] = 7.0x10^-7, you would get a pH of 6.15 for this solution.
The pH of a solution is defined as -log10[H+]. Thus a solution with a hydrogen ion concentration of 10-5M has a pH of 5. [H+] = 10-5 pH = -log[H+] pH = - log [10-5] pH = 5
The pH of a neutral solution with equal concentrations of H+ and OH- ions is 7. This is because the concentration of H+ ions equals the concentration of OH- ions in a neutral solution, resulting in a pH of 7.
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