The volume of a sphere with a diameter of 8cm is about 268cm3
The radius of a sphere with antipodes 8 cm apart is 4 cm. The distance between the antipodes of a sphere is the diameter of the sphere. The radius is half the length of the diameter.
The volume in liters of an 8-inch sphere is about 4.4(4.39304412) liters.
256pi.
Volume of a sphere = 4pi*r^3 2r = d, so Volume of a sphere = 4pi*(4)^3 Volume = 256pi
Volume = pi*102*8 = 800*pi cubic cm
The approximate volume of a sphere with a diameter of 8 inches is 268 cubic inches.
The radius of a sphere with antipodes 8 cm apart is 4 cm. The distance between the antipodes of a sphere is the diameter of the sphere. The radius is half the length of the diameter.
Volume of a sphere = 4/3*pi*radius3 Volume = 2144.660585 cubic cm
The volume in liters of an 8-inch sphere is about 4.4(4.39304412) liters.
256pi.
The volume inside a sphere (that is, the volume of the ball) is given by the formula:-Volume = 4/3πr3where 'r' is the radius of the sphere and 'π' is the constant piThe diameter of a sphere is two times its radius, thus a sphere 8 meters in diameter has a radius of 4 meters.
Volume of a sphere = 4pi*r^3 2r = d, so Volume of a sphere = 4pi*(4)^3 Volume = 256pi
To calculate the volume of an apple, you can approximate it as a sphere. The volume ( V ) of a sphere is given by the formula ( V = \frac{4}{3} \pi r^3 ), where ( r ) is the radius. For an average apple with a diameter of about 7-8 cm, the radius would be approximately 3.5-4 cm. Plugging that into the formula, the volume of an apple would be roughly 150-250 cm³, depending on its size.
Volume = pi*102*8 = 800*pi cubic cm
Volume: pi*7*7*8 = 392*pi cubic cm
150.8 cc
The height of the cone of maximum volume that can be inscribed in a sphere of radius 12 cm is not 16 cm; it is actually 16 cm when considering the relationship between the cone's dimensions and the sphere's radius. The cone's volume is maximized when its height is two-thirds of the sphere's radius, which means the optimal height is ( \frac{2}{3} \times 12 \text{ cm} = 8 \text{ cm} ). Thus, the statement is incorrect; the correct height for maximum volume is 8 cm, not 16 cm.