This is a simultaneous equation question. 4x-4y = -40 4x+43 = y Rearrange the second equation so that all the letters and numbers are in line with the first equation remembering to alter the values of the + and - signs. 4x-4y = -40 4x-y = -43 Subtract the second equation from the first equation remembering that a - - is equal to a + This will leave you with -3y = 3 and by dividing both sides by -3 gives you y = -1 Therefore the solution of the simultaneous equation is x = -11 and y = -1. Substitute these values into the original equations to make sure that your solution is correct.
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
10y plus 40 equals 50y.
280
this equals 818
A number "m" plus 40 equals 60. Therefore, 60 minus 40 equals m. m therefore equals 20.
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
120
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
x = 40
10y plus 40 equals 50y.
280
If 40 plus x equals 25 then x is equal to -15.
this equals 818
A number "m" plus 40 equals 60. Therefore, 60 minus 40 equals m. m therefore equals 20.
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
36 + 35 + 40 + 40 + 40 + 40 + 40 = 271 271 is the answer
The solution to 40 plus 40 times 0 plus 1 is 41. The number name is forty-one.