No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
8x-51 is an expression. It is NOT an equation because there is no equals sign.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
If that's 8x = 120, x = 15
There are only one solution.8x - 15x = 0Combine the 'like' terms on the left side of the equation:-7x = 0Divide each side by -7 :x = 0This are the only solution to the equation.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
[ 8x - 2 = 14 ] is the equation.[ x = 2 ] is the solution to the equation.
8x-51 is an expression. It is NOT an equation because there is no equals sign.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
If that's 8x = 120, x = 15
No.
There are only one solution.8x - 15x = 0Combine the 'like' terms on the left side of the equation:-7x = 0Divide each side by -7 :x = 0This are the only solution to the equation.
Because 8 does not = 7, there is no solution. You write No Sol. Alternatively if you simplify an equation to x = x, that would be All Solutions (any number substituted for x satisfies the equation) * * * * * Wrong! 8x = 7x DOES have a solution and that is x = 0
It's a trivial linear equation in 'x'.You can find the solution like this:-104 = 8xDivide each side by 8:-13 = x
'x' must be zero, so the solution set is [ 0 ].
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no single solution. The solution is in the form of the line whose equation is 8x-y2-2 = 0
Well, lets say your question is 8x-7=8(x-3) you would do 8x-7=8(x-3) 8x-7=8x-24 -8x-7=-8x-24 -7=-24 And from there it would show that there is no solution. No number can make that equation possible. Hope I helped :D