To determine if (-15) is a solution to the equation (y - 3x^2 - 8x = 0), we need to substitute (y = -15) into the equation. This gives us (-15 - 3x^2 - 8x = 0). For (-15) to be a solution, there must be corresponding values of (x) that satisfy the equation. However, without specific values for (x), we cannot conclude that (-15) is a solution.
If that's 8x = 120, x = 15
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
If you mean: 8x = 120 then the value of x is 15
To solve the equation ( 8x - 5(x - 3) = 18 ), first distribute the (-5) to get ( 8x - 5x + 15 = 18 ). This simplifies to ( 3x + 15 = 18 ). Next, subtract 15 from both sides, yielding ( 3x = 3 ). Finally, divide by 3 to find ( x = 1 ).
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
If that's 8x = 120, x = 15
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
[ 8x - 2 = 14 ] is the equation.[ x = 2 ] is the solution to the equation.
If you mean: 8x = 120 then the value of x is 15
To solve the equation ( 8x - 5(x - 3) = 18 ), first distribute the (-5) to get ( 8x - 5x + 15 = 18 ). This simplifies to ( 3x + 15 = 18 ). Next, subtract 15 from both sides, yielding ( 3x = 3 ). Finally, divide by 3 to find ( x = 1 ).
For the equation 3x-5=8x-30, the first thing you do is subtract 3x from both sides of the equation, so you get -5=5x-30. Next you add 30 to both sides, getting 25=5x. Lastly, you divide both sides by 5, leaving the solution of 5=x. Should your equation be 3(x-5)=8x-30, you would first multiply x-5 by 3, getting 3x-15, creating the equation 3x-15=8x-30. You would then subtract 3x from both sides, betting -15=5x-30. Then add 30 to both sides, creating an equation of 15=5x. Divide both sides by 5, and you get a solution of 3-x.
8x = 120divide the equation by 8 8x/8 = 120/8 x = 15
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
No.
There are only one solution.8x - 15x = 0Combine the 'like' terms on the left side of the equation:-7x = 0Divide each side by -7 :x = 0This are the only solution to the equation.
Because 8 does not = 7, there is no solution. You write No Sol. Alternatively if you simplify an equation to x = x, that would be All Solutions (any number substituted for x satisfies the equation) * * * * * Wrong! 8x = 7x DOES have a solution and that is x = 0
'x' must be zero, so the solution set is [ 0 ].