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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.
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What comes next in this sequence 10 30 15 16 48 24 25?
75x3, /2, +1, x3...10 x3=30 /2=15 +1=16 x3=48 /2=24 +1=25 x3=75
What is the solution set for -x3-2x2-x-2?
There can be no solution set because there is no equation or inequality, only an expression.
X cubed plus x equals -2?
x3 + x = -2 => x3 + x + 2 = 0 => x3 + x2 - x2 - x + 2x - 2 = 0 => x2(x+1) - x(x+1) + 2(x+1) = 0 => (x+1)*(x2-x+2) = 0 Setting the first bracket equal to zero gives the only real solution, which is x = -1 The second bracket gives the complex roots, x = ½*[1 +or- i*sqrt(7)]
What is x cubed times 1 half times the squared root of x cubed?
x3*(1/2)*sqrt(x3) = 1/2*x4.5 or 1/2*sqrt(x9)
How do you factorise x cubed take one?
If it's (x3 -1) that you want to factorize, then find the solutions to (x3 -1) = 0.So if P(x) is a polynomial of x, and x=a is a solution for P(x) = 0, then (x - a) is a factor of P(x).So x = 1 solves (x3 -1) = 0, so (x - 1) is a factor. Use long division (x3 -1)/(x-1) = x2 + x + 1. Use the quadratic formula to find the roots of this: -1/2 ± i*sqrt(3)/2, which is complex. So the factorization is:(x3 -1) = (x - 1)( x2 + x + 1)Multiply the polynomials together to check that your answer is correct.
