x3*(1/2)*sqrt(x3) = 1/2*x4.5 or 1/2*sqrt(x9)
The cubed root of 726 is 9. 9 squared is 81
-27 or +27
that equals the cubed root which equals 7.93(2dp)Improved Answer:-The cube root of 5764 is 17.929767475
y times the cube root of x2y
Square root: √27 = 5.196152423 Result of squared root cubed: 5.196152423 x 5.196152423 x 5.196152423 = 140.2961154293 (Or 140.303 to 2 decimal places.)
The cubed root of 726 is 9. 9 squared is 81
-27 or +27
that equals the cubed root which equals 7.93(2dp)Improved Answer:-The cube root of 5764 is 17.929767475
One step you usually want to take is to move any perfect square out of the radical. Example 1, with numbers: root(12) = root(4x3) = root(4) x root(3) = 2 root(3) Example 2, with variables: root(y cubed) = root(y squared times y) = root(y squared) times root(y) = y root(y)
y times the cube root of x2y
Square root: √27 = 5.196152423 Result of squared root cubed: 5.196152423 x 5.196152423 x 5.196152423 = 140.2961154293 (Or 140.303 to 2 decimal places.)
Well, honey, 2 squared is 4 and 3 cubed is 27, so when you multiply them together, you get 108. So, there you have it - 2 squared times 3 cubed equals 108. Math can be a piece of cake when you break it down!
2 times the cube root of 6
Four times the cube root of 2.
The cubed root of a number is the number that when multiplied by itself three times equals the original number. To find the cubed root of 3.62, you would need to find a number that, when multiplied by itself three times, equals 3.62. This number is approximately 1.561.
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xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1