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6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n
[ 25 - 6n ] is.
Here is one way. Start with: 4n - 7 = 5 - 2n add 2n to both sides to give: 6n - 7 = 5 add 7 to both sides to give: 6n = 12 divide both sides by 6 to give: n = 2
T(n) = 25 - 6n
Let the number be 'n', then the calculation becomes :- 5/n - 3 = 7/2n . . . multiply throughout by 2n 10 - 6n = 7 6n = 3 n = 1/2
-5=6n+7 -5-7=6n+7-7 -12=6n -12/6=6n/6 -2=n
15/6n + 6/6n = 21/6n = 7/2n
6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n
I need to solve this problem using the multiplication principle. -5/6n=-10 solution: -5/6n=-10 (- gets canceled) 5/6n=10 ½=6n N=1/6*2 N=1/12
6n+5 = 11
Easy 37 +5=42/6=7 n=7
[ 25 - 6n ] is.
A 6N HCl solution refers to a solution of hydrochloric acid (HCl) where the concentration is 6 normal (6N). This means that the solution contains 6 moles of HCl per liter of solution. It is a common reagent used in laboratory settings for various chemical reactions and analyses.
6n-1 = 5
If you mean: -6n-2n = 16 then -8n = 16 and the solution to the equation is n = -2
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
Here is one way. Start with: 4n - 7 = 5 - 2n add 2n to both sides to give: 6n - 7 = 5 add 7 to both sides to give: 6n = 12 divide both sides by 6 to give: n = 2