0
I'm assuming you mean x^3 + y^3 = z^3, but if you don't, well suck it up. THere actually are two solutions, but both involve the nuber zero. If you are looking for a solution to this without a zero and only integers, it's impossible. There's a long and complicated proof for that but my brother took number theory, i havent yet. i just know that this isn't possible with integers and no zeros. The two cases where it does work is 0^3 +0^3 =0^3 (duh) and 1^3 +0^3 = 1^3
if you need more help, ill probably never see this again, so get owned
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Coach
RafaAdd your answer:
Earn +20 pts
What is the solution to x3 plus 1331 equals y3?
One equation with two unknowns usually does not have a solution.
What x3 plus y3 called?
It is an algebraic expression.
How to factirise this x3 y3 equation?
x3-y3
How do you factor x3 plus y3 divide x plus y?
x^2 - xy + y^2
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is the solution to x3 plus 1331 equals y3?
One equation with two unknowns usually does not have a solution.
Whats y3+x3+z3 equals to?
3xyz
What x3 plus y3 called?
It is an algebraic expression.
How to factirise this x3 y3 equation?
x3-y3
How do you factor x3 plus y3?
(x2 - xy + y2)(x + y)
How do you factor x3 plus y3 divide x plus y?
x^2 - xy + y^2
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
When can a polynomial is said to be sum or difference of two cubes?
When it is of the form x3 + y3 or x3 - y3. x or y can have coefficients that are perfect cubes, or even ratios of perfect cubes eg x3 + (8/27)y3.
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
x3+y3+z3=k?
The required result will be 3xyz
Iy y equals 3 then y3 y3-y equals?
72
